10=1/2(9.8)(t^2)

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Solution for 10=1/2(9.8)(t^2) equation: 



10=1/2(9.8)(t^2)

We move all terms to the left:

10-(1/2(9.8)(t^2))=0



Domain of the equation: 2(9.8)t^2)!=0

t∈R



We multiply all the terms by the denominator


-(1+10*2(9.8)t^2)=0



We calculate terms in parentheses: -(1+10*2(9.8)t^2), so:

1+10*2(9.8)t^2

determiningTheFunctionDomain
10*2(9.8)t^2+1

Wy multiply elements

20t(9+1

Back to the equation:

-(20t(9+1)



We add all the numbers together, and all the variables

-(20t10=0

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